> Suppose an N-diopter lens gives me a sharp focus at 20 inches,
> but I want it to be at, say, 28 inches (for viewing a wide computer-screen).
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>
> David
Feels like there should be a simple rule, doesn't it?
You'd be working with sums of reciprocals though, so no simple addition
rule. Easy enough to derive it, though:
In the example, 'N' is pretty close to 2D.
39.25" (1 meter) divided by 20" = 1.9625D, if it gives you the effect of
seeing the object at infinity.
You need 39.25/28 = 1.4018D *total*, so -0.56D "add".
Close enough for almost anyone, -0.50D.
If you tried to use the 8" difference directly in a formula, you'd get
something like 39.25/8 = 5D, definitely NOT what you want.
(All that supposes you have or want to use no compensation, or focusing
power of your own lens. Post-cataract surgery, e.g.)
Dave
David Combs - 26 Nov 2008 13:45 GMT
>> Suppose an N-diopter lens gives me a sharp focus at 20 inches,
>> but I want it to be at, say, 28 inches (for viewing a wide computer-screen).
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>
>In the example, 'N' is pretty close to 2D.
The above "pretty close to 2D" comes *from* the
*following* sentence-- ie up above you're showing the result of
the calculation, *before* showing where you got it from?
>39.25" (1 meter) divided by 20" = 1.9625D, if it gives you the effect of
>seeing the object at infinity.
By "effect of seeing the obj at infinity", do you mean
that with the glasses on, when my eyes feel totally relaxed,
things at infinity show up sharp -- in fact, sharper than
at any other distance?
Or do you mean "with 20-20 eyes, the feeling (totally relaxed,
no strain at all) I'd get looking at something at infinity --
that FEELING is what I'd feel, WITH the glasses, looking at a
20-inch distant object"?
(That sounds to me more like it. Correct?)
>You need 39.25/28 = 1.4018D *total*, so -0.56D "add".
>Close enough for almost anyone, -0.50D.
Cool. Thanks!
>If you tried to use the 8" difference directly in a formula, you'd get
>something like 39.25/8 = 5D, definitely NOT what you want.
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>
>Dave
> Suppose an N-diopter lens gives me a sharp focus at 20 inches,
> but I want it to be at, say, 28 inches (for viewing a wide computer-screen).
[quoted text clipped - 5 lines]
>
> David
It is better than a rule of thumb. Gauss's imaging formula gives
accurate results. For a lens of focal lengtyh F or power (diopters)
D=1/F, it is
1/Object_distance + 1/Image_distance = 1/F or D.
Read Wikipedia.
Bill

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No rule of thumb would make it easy to add reciprocals. That's why diopters
were invented, cause it's easy to add diopters. It's also why people who
work with lenses eventually learn the diopter value of several common focal
lengths.
For a human with no accommodation, corrected precisely for infinity, a +2.00
lens focuses pretty precisely at 20 inches. +2.00D=1/2m=20"
+1.75D=1/1.75m=.57m=22"
+1.50D=1/1.5m=.67m=26"
+1.25D=1/1.25m=.8m=31"
Obviously, quarter-diopter steps are much smaller up close than when further
away. That's the difficulty.
When the steps don't line up exactly (26" vs 28") common sense usually
dictates whether we round up or down. Less is usually better than more, and
in bright light, depth-of-field usually gives us at least +/-0.25D of
leeway.
-MT
> Suppose an N-diopter lens gives me a sharp focus at 20 inches,
> but I want it to be at, say, 28 inches (for viewing a wide
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>
> David