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Medical Forum / General / Vision / July 2005

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Photoreceptors and sensitivity

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Johannes - 06 Jul 2005 12:04 GMT
Dear forum,

can someone explain me the reason why the rods and cones in our eyes do
differ in their sensitivity to light ? Is this due to chemical
differences in the visual purple that they contain or does the shape
and size of their outer segment play a role as well ?

Any input is very welcome !
Johannes
William Stacy - 06 Jul 2005 14:59 GMT
You are probably correct.  I just know that they were "designed" for
different functions, so their structure, chemistry and neural
connections were optimized for their intended function: cones for fine
detail and color perception, rods for low level light detection and
motion. For the precise differences, I'm sure some of the more
technically oriented scientists will help you out there, or you can
consult a textbook on retina structure and function.

w.stacy, o.d.

ohannes wrote:

> Dear forum,
>
[quoted text clipped - 5 lines]
> Any input is very welcome !
> Johannes
silverblue001@hotmail.com - 06 Jul 2005 19:48 GMT
Well I'm no expert on this topic, but since I'm doing a Physiology
Specialist, I know a little bit about this ...

Light absorbing pigment is embedded within the sensory membranes of
cones and rods.  This pigment is composed of retinal and opsin (a
protein).  The protein opsin differs for each type of photoreceptor
(i.e., differences in amino acid sequences) and determines light
absorption.  In rods, the pigment is Rhodopsin.  In cones, there are
three different types of pigments.  Each pigment absorbs a different
band of the visual spectrum (S cones, blue, ~420 nm; M cones, green,
~525 - 545 nm; L cones, red, ~ 552 - 557 nm).  Really, each cone type
has it's own absorption curve (responds to a range of wavelengths -
some more than others).  Any colour we see is a varying mixture of
these primary colours ... but yeah, I won't go into the details of
colour vision ...

Hope that was clear enough ...
Quick - 06 Jul 2005 19:59 GMT
> In cones, there are
> three different types of pigments.  Each pigment absorbs
[quoted text clipped - 5 lines]
> mixture of these primary colours ... but yeah, I won't go
> into the details of colour vision ...

I don't need details but is there anything that can be
done so I don't need to use a magic marker on the
tags of my pants -- "Navy Blue", "Black", "dark Green"?
I didn't need this when younger.

-Quick
Mike Tyner - 06 Jul 2005 20:18 GMT
> I don't need details but is there anything that can be
> done so I don't need to use a magic marker on the
> tags of my pants -- "Navy Blue", "Black", "dark Green"?
> I didn't need this when younger.

Brighter light in the closet. :)

-MT
Quick - 06 Jul 2005 21:24 GMT
>> I don't need details but is there anything that can be
>> done so I don't need to use a magic marker on the
>> tags of my pants -- "Navy Blue", "Black", "dark Green"?
>> I didn't need this when younger.
>
> Brighter light in the closet. :)

yes... small nuclear reactor. I can still differentiate slight
color differences in bright sunlight.

-Quick
William Stacy - 06 Jul 2005 23:13 GMT
> yes... small nuclear reactor. I can still differentiate slight
> color differences in bright sunlight.

Sounds like either the magic marker or a live-in fashion consultant are
in order...

w.stacy, o.d.
Johannes - 06 Jul 2005 23:37 GMT
Many thanks for yout input, but I have a follow-up :
What happens to the signalling chain of the rods if they are light
adapted ?
Their rhodopsin is still beeing bleached and they should be
hyperpolarized so that the following cells in the retina are not beeing
inhibited.
How does the retina know that it shouldn´t pay any more attention to
that signal but listen to the cones instead ?

Johannes
Mike Tyner - 07 Jul 2005 04:26 GMT
> How does the retina know that it shouldn´t pay any
> more attention to that signal but listen to the cones instead ?

The rods are saturated and never recover in bright light. With rhodopsin
exhausted, they can't stimulate depolarization and don't even contribute
noise.

I'm also curious how rods and cones are made sensitive over two such widely
different ranges.

There's great information at
(http://www.psych.ndsu.nodak.edu/mccourt/Psy460/Sensitivity%20Regulation/sensitiv
ity%20regulation.html
).
If the link doesn't work, google "rod cone intensity regulation" without the
quotes.

-MT
silverblue001@hotmail.com - 07 Jul 2005 12:06 GMT
I'm not sure how detailed an answer you want, so I'm going to write
this with the assumption that you have some working knowledge of the
neuron and also some basic physiological/biochemical principles  (you
may even know most of this already ;).

In the absence of light:
1.  Retinal binds to a binding site in opsin.
2.  Resting levels of cGMP are (relatively) high, causing cGMP-gated
sodium channels to open.  Potassium channels are also open.  Sodium
influx is greater than potassium efflux, so the rod remains depolarized
(average membrane potential:  - 40 mV).  Glutamate (neurotransmitter)
is tonically released while the neuron is at rest.

Because of the sensitivity of Rhodopsin, it can be activated by as
little as a single proton.  When this occurs ...
1.  Retinal is converted from its 11-cis isomer to its all-trans
isomer.  Because of this structural change, it cannot bind to opsin any
longer***.  This activated form of retinal (often denoted R*),
activates the protein transducin (T*).
2.  The activated transducin then activates a cGMP phosphodiesterase,
which converts cGMP to GMP.
3.  The above decrease in cGMP levels leads to the closure of sodium
channels.  Because there is less sodium influx, but continued potassium
efflux, the inside of the cell is hyperpolarized (to about -70 mV).
4.  The release of glutamate onto the bipolar cells decreases.  Bright
light will close all sodium channels, and stop all neurotransmitter
release.  Dimmer light will cause a response that is proportional to
the light intensity.

*** This active form of retinal is released from the pigment (this is
what you referred to as "bleaching").  It diffuses out of the rod and
into the pigment epithelium.  There it reverts back to the trans
configuration and moves back into the rod to again bind to the opsin.
This regeneration allows a continued light sensitivity of
photoreceptors.  In fact, even in intense lighting conditions, a
significant number of active photoreceptor molecules is maintained.

Yes, so that was a crash course in the physiology of the retina ;) (a
lot of things were left out, but they're not necessary for a basic
understanding). Hope it helped!

> Many thanks for yout input, but I have a follow-up :
> What happens to the signalling chain of the rods if they are light
[quoted text clipped - 6 lines]
>
> Johannes
Johannes - 08 Jul 2005 00:12 GMT
This is getting quite interesting for me (surely for others as well).
Mike wrote :"The rods are saturated and never recover in bright light.
With rhodopsin exhausted, they can't stimulate depolarization and don't
even contribute noise." I can understand that very well because it
explains the long recovery time of the rods that can be seen in the
dark adaptation curve. More than that it answers my question about the
the bipolar cells´ behavior in the light adapted state : It doesn´t
have to listen to the rods any more because they don´t signal any
more.
Now silverblue001 wrote :"... In fact, even in intense lighting
conditions, a significant number of active photoreceptor molecules is
maintained." Do I have to understand that in opposition to the
statement above and does it mean that the rods do maintain some
sensitivity during intense lighting situations ? If so, I would think
that they keep on producing some kind of signal. And that leads me back
to my question : How does the bipolar cell know when to ignore the
rods´ signal ? If I show some lack of understanding here, please help
me fill it in !

Johannes
silverblue001@hotmail.com - 08 Jul 2005 03:43 GMT
> Now silverblue001 wrote :"... In fact, even in intense lighting
> conditions, a significant number of active photoreceptor molecules is
[quoted text clipped - 5 lines]
> rods´ signal ? If I show some lack of understanding here, please help
> me fill it in !

In high luminance conditions, vision is *primarily* a function of
cones.  That doesn't mean that ALL of the rods are inactive.  Bipolar
cells DO NOT ignore the signals.
RM - 08 Jul 2005 04:09 GMT

This is an extremely complicated topic.  Unless some of the eyedocs here are
also retinal electrophysiologists, you might not get complete answers to all
your questions.  I suggest doing a little googling and you will find some
additional info most likely from journal references or website of university
research groups.

I will mention two important points that haven't already been made by others
here that might help you understand the complexity of this topic

1.  There are many different types of bipolar cells.  Some receive input
from only rods.  Some receive input from only cones. And some receive input
from a mixture of both.  Thus there are parallel as well as mixed channel of
neural input from photoreceptors into the bipolars.

2.  Aside from receptor-level light adaptation processes (opsin
regeneration, rhodopsin phosphorylation, etc) there are also postreceptor
processes.  There are other cells in the retina, for example horizontal
cells, that feedback onto photoreceptors and also influence the bipolars.
These cells can modify neural responsiveness to both high and low light
levels.

I know enough about this topic to know that I don't know very much!
Good luck!
 
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